c语言加减乘除计算器程序代码(c语言加减乘除编程)
求可以计算加减乘除的计算器c语言代码
#includestdio.h
#includestring.h
void nextshow(){
printf("\t\t-\n");
printf("\t\t-请选择计算方法");
printf("\n\t\t-");
printf("1.加法\n");
printf("\t\t-2.减法\n");
printf("\t\t-3.乘法\n");
printf("\t\t-4.除法\n");
printf("\t\t-\n");
printf("请选择:");
}
int main(){
int h;
char choose;
char choosen[16];
char pass1[2]={49};
char pass2[2]={50};
char pass3[2]={51};
char pass4[2]={52};
char pass5[2]={53};
float leftcount,rightcount,last;
int mid=0;
void nextshow();
printf("\n\n");
printf("\t\t-----------------------------\n");
printf("\t\t-\n");
printf("\t\t-\n");
printf("\t\t-请选择计算方法\n");
printf("\t\t-1.加法\n");
printf("\t\t-2.减法\n");
printf("\t\t-3.乘法\n");
printf("\t\t-4.除法\n");
printf("\t\t-5.退出程序\n");
printf("\t\t-\n");
printf("\t\t-\n");
printf("\t\t-----------------------------\n");
printf("请选择:");
sign:
for(;;){
gets(choosen);
h=strcmp(choosen,pass1);
if(h==0){
choose='1';
break;
}
h=strcmp(choosen,pass2);
if(h==0){
choose='2';
break;
}
h=strcmp(choosen,pass3);
if(h==0){
choose='3';
break;
}
h=strcmp(choosen,pass4);
if(h==0){
choose='4';
break;
}
h=strcmp(choosen,pass5);
if(h==0)
return 1;
else
printf("输入有误，请重试:");
}
if(choose=='1'){
printf("请输入加数:");
scanf("%f",leftcount);
printf("请输入加数:");
scanf("%f",rightcount);
last=leftcount+rightcount;
printf("---------结果为:%f\n",last);
}
if(choose=='2'){
printf("请输入被减数:");
scanf("%f",leftcount);
printf("请输入减数:");
scanf("%f",rightcount);
last=leftcount-rightcount;
printf("---------结果为:%f\n",last);
}
if(choose=='3'){
printf("请输入乘数:");
scanf("%f",leftcount);
printf("请输入乘数:");
scanf("%f",rightcount);
last=leftcount*rightcount;
printf("---------结果为:%f\n",last);
}
if(choose=='4'){
printf("请输入被除数:");
scanf("%f",leftcount);
printf("请输入除数:");
while(1){
scanf("%f",rightcount);
if(rightcount!=0)
break;
printf("有异常被抛出:除数为0 请重试:");
}
last=leftcount/rightcount;
printf("---------结果为:%f\n",last);
}
sign2:
printf("\n在此结果的基础上继续计算吗?\n");
printf("1.是\n2.否\n3.退出程序\n请选择:");
getchar();
for(;;){
gets(choosen);
h=strcmp(choosen,pass1);
if(h==0){
choose='1';
break;
}
h=strcmp(choosen,pass2);
if(h==0){
choose='2';
break;
}
h=strcmp(choosen,pass3);
if(h==0)
return 1;
else
printf("输入有误，请重试:");
}
if(choose=='1'){
leftcount=last;
nextshow();
for(;;){
gets(choosen);
h=strcmp(choosen,pass1);
if(h==0){
choose='1';
break;
}
h=strcmp(choosen,pass2);
if(h==0){
choose='2';
break;
}
h=strcmp(choosen,pass3);
if(h==0){
choose='3';
break;
}
h=strcmp(choosen,pass4);
if(h==0){
choose='4';
break;
}
else
printf("输入有误，请重试:");
}
if(choose=='1'){
printf("请输入加数:");
scanf("%f",rightcount);
last=leftcount+rightcount;
printf("---------结果为:%f\n",last);
}
if(choose=='2'){
printf("请输入减数:");
scanf("%f",rightcount);
last=leftcount-rightcount;
printf("---------结果为:%f\n",last);
}
if(choose=='3'){
printf("请输入乘数:");
scanf("%f",rightcount);
last=leftcount*rightcount;
printf("---------结果为:%f\n",last);
}
if(choose=='4'){
printf("请输入除数:");
while(1){
scanf("%f",rightcount);
if(rightcount!=0)
break;
printf("有异常被抛出:除数为0 请重试:");
}
last=leftcount/rightcount;
printf("---------结果为:%f\n",last);
}
goto sign2;
}
if(choose=='2'){
nextshow();
goto sign;
}
}
c语言加减乘除运算代码
方法如下：
设备：华为笔记本。
系统：win7。
软件：Code Blocks。
版本：8.0.11。
1、首先打开Code Blocks软件，新建一个C语言文件，如下图所示。
2、接下来在C语言文件中编写加减乘除运算代码，如下图所示。
3、然后点击构建菜单下面的编译当前文件选项，如下图所示。
4、最后运行程序就可以得到加减乘除运算的结果了，如下图所示。
c语言编四则运算器程序
分类: 电脑/网络 程序设计 其他编程语言
问题描述:
功能为;首先有一个界面问"请输入你想进行运算的对象个数”
这个数在一至5之间
然后出来界面让输入算术式
然后输入结果
然后有计算机判断对错
解析:
哈哈,刚好,我也在学C语言,碰巧,这几天也正在思考编写计算器的问题.网上应该能找到经典的C程序计算器,这个是我独立写出来的.
我只学到数组这里.所以没用到堆栈,指针之类的.主要用数组,循环与函数调用实现.完全是入门级.
支持四则运算和指数运算（用h符）。
数据类型为float型。
算术式最大长度可以通过修改程序中的数组长度和“I”值更该，没有具体规定，使用时要注意运算结果的溢出问题。
对错误的算术式有一定的检查功能。
程序代码如下：
#includemath.h
float sss(float d[],char e[],int I)
{int i,n;
for(i=0;i=I;n=++i)
{if(e[i]==0)
{printf("The answer is:--: %f\n",d[i]);i=I;}
else
{if(e[i]-e[i+1]-5)
{switch(e[i])
{case 80: d[i+1]=d[i]+d[i+1];break;
case 81: d[i+1]=d[i]-d[i+1];break;
case 90: d[i+1]=d[i]*d[i+1];break;
case 91: d[i+1]=d[i]/d[i+1];break;
case 100: d[i+1]=pow(d[i],d[i+1]);break;
default :printf("Sorry! Some Error unknow...");break;}
for(n=i;i=I;i++)
{d[i]=d[i+1],e[i]=e[i+1];
if(e[i]==0) i=I;}
if(n==0) i=n-1;
else i=n-2;}}}}
main()
{float d[32];
char e[32];
int i,I=31,n;
printf("\n\n");
for(i=0;i=I;i++)
{scanf("%f%c",d[i],e[i]);
switch(e[i])
{case '+': e[i]=80;break;
case '-': e[i]=81;break;
case '*': e[i]=90;break;
case '/': e[i]=91;break;
case 'h': e[i]=100;break;
case '=': e[i]=0,i=I;break;
default: printf("Oper %d is Error! ---- %c -ChangeTo:one of + - * / h =\n",i+1,e[i]);}}
printf("\n");
sss(d,e,I);}
直接从我的.c文件里复制出来的.
使用时输入格式例如:123*456-789/369+852h2-741= 然后回车.
852h2表示852的2次方.记得以等号结束.不支持括号(正在努力).
在这支持的32次运算(包括等号).
简单的用c语言写一个计算器程式，加减乘除能用就好
简单的用c语言写一个计算器程式，加减乘除能用就好 #include"stdio.h"
void main()
{
float a,b,c;
char e;
printf("input a,e,b\n");/*输入两个数和符号，例如3+8*/
scanf("%f%c%f",a,e,b);
switch(e)
{
case '+':c=a+b;break;
case '-':c=a-b;break;
case '*':c=a*b;break;
case '/':
if(b==0.0) printf("error\n");
else c=a/b;break;
}
printf("%f%c%f=%f",a,e,b,c);
}
如何用vc++编写一个简单的（只有加减乘除）计算器程式?
先设定介面如下
加法按钮程式码
void CMy03Dlg::OnBnClickedButton1()
{
TODO：在此新增控制元件通知处理程式程式码
UpdateData(TRUE);
m_Nub3=m_Nub1+m_Nub2;
UpdateData(FALSE);
}
减法按钮程式码
void CMy03Dlg::OnBnClickedButton2()
{
TODO：在此新增控制元件通知处理程式程式码
UpdateData(TRUE);
m_Nub3=m_Nub1-m_Nub2;
UpdateData(FALSE);
}
乘法按钮程式码
void CMy03Dlg::OnBnClickedButton3()
{
TODO：在此新增控制元件通知处理程式程式码
UpdateData(TRUE);
m_Nub3=m_Nub1*m_Nub2;
UpdateData(FALSE);
}
除法按钮程式码
void CMy03Dlg::OnBnClickedButton4()
{
TODO：在此新增控制元件通知处理程式程式码
UpdateData(TRUE);
if(m_Nub2!=0)
m_Nub3=m_Nub1 / m_Nub2;
else
AfxMessageBox("被除数不能为0");
UpdateData(FALSE);
}
清除按钮程式码
void CMy03Dlg::OnBnClickedButton5()
{
TODO：在此新增控制元件通知处理程式程式码
UpdateData(TRUE);
m_Nub3=0;
m_Nub1=0;
m_Nub2=0;
UpdateData(FALSE);
}
结束按钮程式码
void CMy03Dlg::OnBnClickedButton6()
{
TODO：在此新增控制元件通知处理程式程式码
CDialog::OnOK();
}
如果只允许在输入框中输入资料应该怎样处理？
制作托盘程式
目的：在工作列中建立一个图示，使该程式永远驻留在记忆体中。例如邮件检查程式可以作为驻留程式，一旦有邮件来了，就可以接收邮件。
Shell_NotifyIcon函式传送讯息来增加、删除、修改工作列的图示
BOOL TrayMessage(HWND hWnd, DWORD dwMessage, HICON hIcon, PSTR pszTip)
{
BOOL res;
NOTIFYICONDATA tnd;
tnd.cbSize = sizeof(NOTIFYICONDATA);
tnd.hWnd = hWnd;
tnd.uID = IDI_ICON1;
tnd.uFlags = NIF_MESSAGE|NIF_ICON|NIF_TIP;
tnd.uCallbackMessage = WM_MY_TRAY_NOTIFICATION;
tnd.hIcon = hIcon;
lstrcpyn(tnd.szTip, pszTip, sizeof(tnd.szTip));
res = Shell_NotifyIcon(dwMessage, tnd); dwMessage为NIM_ADD从工作列中新增图示、NIM_DELETE从工作列中删除图示、NIM_MODIFY改变工作列中图示
if (hIcon)
DestroyIcon(hIcon);
return res;
}
定义一个回拨讯息：WM_MY_TRAY_NOTIFICATION
在DLG的CPP档案中，
#define WM_MY_TRAY_NOTIFICATION WM_USER+100
为对话方块新增讯息对映ON_MESSAGE(WM_MY_TRAY_NOTIFICATION,OnTrayNotification)
在DLG的标头档案中应该有
public:
long m_Nub1;
float m_Nub3;
CBitmapButton Button;
afx_msg void OnBnClickedButton1();
long m_Nub2;
afx_msg void OnBnClickedButton2();
afx_msg void OnBnClickedButton4();
afx_msg void OnBnClickedButton5();
afx_msg void OnBnClickedButton3();
afx_msg void OnBnClickedButton6();
afx_msg void OnBnClickedButton7();
afx_msg LRESULT OnTrayNotification(WPARAM wparam, LPARAM lparam);
在DLG的CPP档案中应该有
BEGIN_MESSAGE_MAP(CMailCheckDlg, CDialog)
……
ON_MESSAGE(WM_MY_TRAY_NOTIFICATION,OnTrayNotification)
……
END_MESSAGE_MAP()
并定义一个回拨讯息函式
LRESULT CMailCheckDlg::OnTrayNotification(WPARAM wparam, LPARAM lparam)
{
switch (lparam )
{
case WM_RBUTTONUP:
case WM_LBUTTONDBLCLK:修改不同的按钮处理事件，以观察图示退出效果。
ShowWindow(SW_SHOW);
TrayMessage(m_hWnd, NIM_DELETE, NULL, "");从工作列中删除图示
}
return 0;
}
在对话方块视窗上新增“驻留”按钮，双击按钮新增程式码
void CMailCheckDlg::OnBnClickedButton1()
{
TODO：在此新增控制元件通知处理程式程式码
下面程式向工作列新增图示
TrayMessage(m_hWnd, NIM_ADD, NULL, "计算器程式");
TrayMessage(m_hWnd, NIM_MODIFY, m_hIcon, "计算器程式");
ShowWindow(SW_HIDE);
用MFC编写一个简单的加减乘除计算器
我有程式，加31782771群
c语言计算器程式设计包含加减乘除简单的函式运算
实用计算器之程式设计
[摘 要]多用计算器的构思及设计程式码
[关键词]多用计算器；设计
数值计算可以说是日常最频繁的工作了，WIN98提供了“计算器”软体供使用者使用，该软体可以处理一般的一步四则运算，例如：3+2、5/3等等，但在日常中使用者经常遇到多步四则运算问题，例如：3+4*5-4/2，45*34/2+18*7等等，那么该个计算器就无法胜任了，作者制作了一个实用的计算器，该计算器新增不少功能：（程式介面如图）
1．可以实现连续的四则运算
2．可以实现输入式子的显示
3．可以方便计算个人所得税
4．滑鼠、键盘均可输入资料
5．操作介面友好
6．击键可发声
构建该个计算器所需研究及解决的核心问题有如下几个：1、连乘求值?2、字元显示 3、键盘输入?4、击键发声?5、个人所得税法规，为了使大家对程式有更一步认识，现将程式码提供给读者参考：
*定义阵列及窗体变数
Dim number2(0 To 50) As Double
Dim number(0 To 50) As Double
Dim z As Integer
Dim k As Integer, r As Integer
Dim j As Integer
Dim str As String
*呼叫名为“playsound”的API函式
Private Declare Function PlaySound Lib "winmm.dll" Alias "PlaySoundA" (ByVal lpszName As String, ByVal hModule As Long, ByVal dwFlags As Long) As Long
Private Const SND_FILENAME = H20000?
Private Const SND_ASYNC = H1?
Private Const SND_SYNC = H0
*判断通用过程
Sub pianduan(p As String)
r = 0
Dim i As Integer, l As Integer, h As Integer
h = 0
i = 1
If InStr(Trim$(p), "*") 0 Then
k = k + 1
End If
If InStr(Trim$(p), "/") 0 Then
r = r + 1
End If
End Sub
*连乘通用过程(略)
*各按钮事件过程
Private sub Command1_Click(Index As Integer)
PlaySound App.Path "\start.wav", 0, SND_SYNC
Text1.Text = Text1.Text + Command1(Index).Caption
Text2.Text = Text2.Text + Command1(Index).Caption
Text1.SetFocus
End Sub
rivate sub Command10_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
str = Text3.Text
End Sub
Private sub Command11_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
Text3.Text = str
End Sub
rivate sub Command2_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
Dim totle As Double
Dim n As Integer
Call pianduan(Text1.Text)
If k = 1 Or r = 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
Text2.Text = Text2 + "+"
z = z + 1
Text1.SetFocus
End Sub
rivate sub Command3_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
Dim totle As Double
Dim n As Integer
Call pianduan(Text1.Text)
If k = 1 Or r = 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
Text2.Text = Text2 + "-"
Text1.Text = Text1.Text "-"
z = z + 1
Text1.SetFocus
End Sub
Private sub Command4_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
Text2.Text = Text2.Text + "*"
Text1.Text = Text1.Text + "*"
Text1.SetFocus
End Sub
rivate sub Command5_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
Text2.Text = Text2 + "/"
Text1.Text = Text1 + "/"
Text1.SetFocus
End Sub
Private sub Command6_Click()
PlaySound App.Path "\sound.wav", 0, SND_SYNC
Dim totle As Double
Dim n As Integer
Call pianduan(Text1.Text)
If k = 1 Or r = 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
z = z + 1
Dim dengyu As Double
Dim v As Integer
For v = 0 To 50
dengyu = dengyu + number2(v)
Next v
If dengyu 0 Then
Text3.ForeColor = HFF
Else
Text3.ForeColor = HFF0000
End If
Text3.Text = dengyu
Text1.SetFocus
If Len(Text3.Text) = 14 Then
calcresult.Show
End If
End Sub
rivate sub Command7_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
z = 0: k = 0: r = 0: j = 0
Dim i As Integer
For i = 0 To 50
number(i) = 0
number2(i) = 0
Next i
Text1.Text = ""
Text2.Text = ""
Text3.Text = ""
Text1.SetFocus
End Sub
rivate sub Command8_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
If Val(Text3.Text) = 0 Then
MsgBox "除数不能为0！"
Exit Sub
End If
Text3.Text = 1 / Val(Text3.Text)
End Sub
Private sub Command9_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
Text3.ForeColor = HFF0000
Text3.Text = Val(Text3.Text) * Val(Text3.Text)
End Sub
rivate sub muninter_Click()
Dim i
i = Shell("C:\Program Files\InterExplorer\iexplore.exe", vbMaximizedFocus)
End Sub
rivate sub munmp3_Click()
Dim i
i = Shell("C:\Program Files\Windows Media Player\mplayer2", vbNormalNoFocus)
End Sub
Private sub mun *** _Click()
Dialog.Show
End Sub
rivate sub muntax_Click()
tax.Show
End Sub
rivate sub munver_Click()
ver.Show
End Sub
rivate sub notepad_Click()
Dim i
i = Shell("c:\windows\notepad", vbNormalFocus)
End Sub
Private sub Text1_KeyPress(KeyAscii As Integer)
PlaySound App.Path "\start.wav", 0, SND_SYNC
Dim num As Integer
num = Val(KeyAscii)
If num 47 And num 58 Then
Text1.Text = Text1.Text + CStr(num - 48)
Text2.Text = Text2.Text + CStr(num - 48)
End If
If num = 46 Then
Text1.Text = Text1.Text + "."
Text2.Text = Text2.Text + "."
End If
If KeyAscii = 43 Then
Dim totle As Double
Dim n As Integer
Call pianduan(Text1.Text)
If k = 1 Or r = 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
Text2.Text = Text2 + "+"
z = z + 1
End If
If KeyAscii = 45 Then
Call pianduan(Text1.Text)
If k = 1 Or r = 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
Text2.Text = Text2 + "-"
Text1.Text = Text1.Text "-"
z = z + 1
End If
If KeyAscii = 42 Then
Text2.Text = Text2.Text + "*"
Text1.Text = Text1.Text + "*"
End If
If KeyAscii = 47 Then
Text2.Text = Text2.Text + "/"
Text1.Text = Text1.Text + "/"
End If
If KeyAscii = vbKeyReturn Then
PlaySound App.Path "\sound.wav", 0, SND_SYNC
Call pianduan(Text1.Text)
If k = 1 Or r = 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
z = z + 1
Dim dengyu As Double
Dim v As Integer
For v = 0 To 50
dengyu = dengyu + number2(v)
Next v
If dengyu 0 Then
Text3.ForeColor = HFF
Else
Text3.ForeColor = HFF0000
End If
Text3.Text = dengyu
End If
If KeyAscii = vbKeyEscape Then
z = 0: k = 0: r = 0: j = 0
Dim i As Integer
For i = 0 To 50
number(i) = 0
number2(i) = 0
Next i
Text1.Text = ""
Text2.Text = ""
Text3.Text = ""
Text1.SetFocus
End If
If Len(Text3.Text) = 14 Then
calcresult.Show
End If
End Sub
rivate sub Text3_Change()
tax2.Text1 = Text3.Text
End Sub
用c语言编写能运算加减乘除的计算器程式，用到栈
#include "stdio.h"
#include "string.h"
#include "ctype.h"
#include "math.h"
expression evaluate
#define iMUL 0
#define iDIV 1
#define iADD 2
#define iSUB 3
#define iCap 4
#define LtKH 5
#define RtKH 6
#define MaxSize 100
void iPush(float);
float iPop();
float StaOperand[MaxSize];
int iTop=-1;
char Srcexp[MaxSize];
char Capaexp[MaxSize];
char RevPolishexp[MaxSize];
float NumCapaTab[26];
char validexp[]="*/+-()";
char NumSets[]="0123456789";
char StackSymb[MaxSize];
int operands;
void NumsToCapas(char [], int , char [], float []);
int CheckExpress(char);
int PriorChar(char,char);
int GetOperator(char [], char);
void counterPolishexp(char INexp[], int slen, char Outexp[]);
float CalcRevPolishexp(char [], float [], char [], int);
void main()
{
int ilen;
float iResult=0.0;
printf("enter a valid number string:\n");
memset(StackSymb,0,MaxSize);
memset(NumCapaTab,0,26); A--NO.1, B--NO.2, etc.
gets(Srcexp);
ilen=strlen(Srcexp);
printf("source expression:%s\n",Srcexp);
NumsToCapas(Srcexp,ilen,Capaexp,NumCapaTab);
printf("Numbers listed as follows:\n");
int i;
for (i=0; ioperands; ++i)
printf("%.2f ",NumCapaTab[i]);
printf("\nCapaexp listed in the following:\n");
printf("%s\n",Capaexp);
ilen=strlen(Capaexp);
counterPolishexp(Capaexp,ilen,RevPolishexp);
printf("RevPolishexp:\n%s\n",RevPolishexp);
ilen=strlen(RevPolishexp);
iResult=CalcRevPolishexp(validexp, NumCapaTab, RevPolishexp,ilen);
printf("\ncounterPolish expression:\n%s%.6f\n",Srcexp,iResult);
}
void iPush(float value)
{
if(iTopMaxSize) StaOperand[++iTop]=value;
}
float iPop()
{
if(iTop-1)
return StaOperand[iTop--];
return -1.0;
}
void NumsToCapas(char Srcexp[], int slen, char Capaexp[], float NumCapaTab[])
{
char ch;
int i, j, k, flg=0;
int sign;
float val=0.0,power=10.0;
i=0; j=0; k=0;
while (islen)
{
ch=Srcexp[i];
if (i==0)
{
sign=(ch=='-')?-1:1;
if(ch=='+'||ch=='-')
{
ch=Srcexp[++i];
flg=1;
}
}
if (isdigit(ch))
{
val=ch-'0';
while (isdigit(ch=Srcexp[++i]))
{
val=val*10.0+ch-'0';
}
if (ch=='.')
{
while(isdigit(ch=Srcexp[++i]))
{
val=val+(ch-'0')/power;
power*=10;
}
} end if
if(flg)
{
val*=sign;
flg=0;
}
} end if
write Capaexp array
write NO.j to array
if(val)
{
Capaexp[k++]='A'+j;
Capaexp[k++]=ch;
NumCapaTab[j++]=val; A--0, B--1,and C, etc.
}
else
{
Capaexp[k++]=ch;
}
val=0.0;
power=10.0;
i++;
}
Capaexp[k]='\0';
operands=j;
}
float CalcRevPolishexp(char validexp[], float NumCapaTab[], char RevPolishexp[], int slen)
{
float sval=0.0, op1,op2;
int i, rt;
char ch;
recursive stack
i=0;
while((ch=RevPolishexp[i]) islen)
{
switch(rt=GetOperator(validexp, ch))
{
case iMUL: op2=iPop(); op1=iPop();
sval=op1*op2;
iPush(sval);
break;
case iDIV: op2=iPop(); op1=iPop();
if(!fabs(op2))
{
printf("overflow\n");
iPush(0);
break;
}
sval=op1/op2;
iPush(sval);
break;
case iADD: op2=iPop(); op1=iPop();
sval=op1+op2;
iPush(sval);
break;
case iSUB: op2=iPop(); op1=iPop();
sval=op1-op2;
iPush(sval);
break;
case iCap: iPush(NumCapaTab[ch-'A']);
break;
default: ;
}
++i;
}
while(iTop-1)
{
sval=iPop();
}
return sval;
}
int GetOperator(char validexp[],char oper)
{
int oplen,i=0;
oplen=strlen(validexp);
if (!oplen) return -1;
if(isalpha(oper)) return 4;
while(ioplen validexp[i]!=oper) ++i;
if(i==oplen || i=4) return -1;
return i;
}
int CheckExpress(char ch)
{
int i=0;
char ;
while((=validexp[i]) ch!=) ++i;
if (!)
return 0;
return 1;
}
int PriorChar(char curch, char stach)
{
栈外优先顺序高于()栈顶优先顺序时，才入栈
否则(=)，一律出栈
if (curch==stach) return 0; 等于时应该出栈
else if (curch=='*' || curch=='/')
{
if(stach!='*' stach!='/')
return 1;
}
else if (curch=='+' || curch=='-')
{
if (stach=='(' || stach==')')
return 1;
}
else if (curch=='(')
{
if (stach==')')
return 1;
}
return 0;
}
void counterPolishexp(char INexp[], int slen, char Outexp[])
{
int i, j, k,pr;
char t;
i=0;
j=k=0;
while (INexp[i]!='=' islen)
{
if (INexp[i]=='(')
StackSymb[k++]=INexp[i];
iPush(*(INexp+i));
else if(INexp[i]==')')
{
if((t=iPop())!=-1)
while((t=StackSymb[k-1])!='(')
{
Outexp[j++]=t;
k--;
}
k--;
}
else if (CheckExpress(INexp[i])) is oparator
{
printf("operator %c k=%d\n",INexp[i],k);
while (k)
{
iPush(*(INexp+i));
if(pr=PriorChar(INexp[i],StackSymb[k-1]))
break;
else
{
if ((t=iPop())!=-1)
t=StackSymb[k-1]; k--;
Outexp[j++]=t;
}
} end while
StackSymb[k++]=INexp[i]; mon process
}
else if() 变数名
{
printf("operand %c k=%d\n",INexp[i],k);
Outexp[j++]=INexp[i];
}
i++;
}
while (k)
{
t=StackSymb[k-1]; k--;
Outexp[j++]=t;
}
Outexp[j]='\0';
}
注：程式源于“百度知道”
用verilog编写一个最简单的加减乘除的计算器的程式
verilog是有加法器乘法器的。也直接识别 + - * / 符号。
module kjasdja(a,option,b,result);
input option,a,b;
output result;
always @(a,b,option)
begin
result_r=0; 结果暂存器清零
case(option)
+:result_r=a+b;
-:result_r=a-b;
*:result_r=a*b;
/:result_r=a/b;
assign result =result_r;
endmodule
大概演算法就这样。写的仓促，语法可能有误。另外除法reg型别只能储存整数部分，小数通过移位操作实现，比较麻烦。比如3/5=0.6
做的时候先3=30，然后30/5=6,然后对6在数码管的显示进行调整就好。把6显示在小数点后面1位就好
用vb编写一个计算器程式，实现加减乘除，
Dim v As Boolean
Dim s As Integer
Dim X As Double
Dim Y As Double
Private Sub Command1_Click(Index As Integer)
If Form1.Tag = "T" Then
If Index = 10 Then
Text1.Text = "0"
Else
Text1.Text = Command1(Index).Caption
End If
Form1.Tag = ""
Else
Text1.Text = Text1.Text Command1(Index).Caption
End If
End Sub
Private Sub Command2_Click(Index As Integer)
Form1.Tag = "T"
If v Then
X = Val(Text1.Text)
v = Not v
Else
Y = Val(Text1.Text)
Select Case s
Case 0
Text1.Text = X + Y
Case 1
Text1.Text = X - Y
Case 2
Text1.Text = X * Y
Case 3
If Y 0 Then
Text1.Text = X / Y
Else
MsgBox ("不能以0为除数")
Text1.Text = X
v = False
End If
Case 4
Y = 0
v = False
End Select
X = Val(Text1.Text)
End If
s = Index
End Sub
Private Sub Frame1_DragDrop(Source As Control, X As Single, Y As Single)
End Sub
控制元件自己新增吧，空间名要和程式码名一致
求一简单的加减乘除计算器c++程式
#includestdio.h
#includemath.h
void main()
{
float a,b;
char C;
while(1)
{
scanf("%f%c%f",a,C,b);
if((C!='+')(C!='-')(C!='*')(C!='/'))
break;
switch(C)
{
case '+': printf("%f+%f=%f",a,b,a+b);
break;
case '-': printf("%f-%f=%f",a,b,a-b);
break;
case '*': printf("%f*%f=%f",a,b,a*b);
break;
case '/': printf("%f/%f=%f",a,b,a/b);
break;
}
}
}
想改成按1 2 3 4分别为加减乘除，只需要将程式中的+ - * / 改成1 2 3 4即可。按除了+ - * / 以外的键就会退出。
用c++语言编写一个简单的计算器程式，会加减乘除就行，本人初学不太会，特训求帮助
这个是最简单，简陋的计算器。很多情况没考虑进去，例如除数不能为0之类的，真要写完整的话程式码还要更多。
程式码如下： #include iostreamusing namespace std;int main(){ float a, b, result; char operation; cout "请输入算式，如1+2并回车：" endl; cin a operation b; switch(operation) { case '+': result = a + b; break; case '-': result = a - b; break; case '*': result = a * b; break; case '/': result = a / b; break; default: cout "输入非法，程式退出！" endl; return -1; } cout endl "结果为：" endl a operation b "=" result endl; return 0;}
知道switch函式 吗 用这个就行
建俩个int型变数 一个字元型变数
C语言计算器 功能要求: 可以输入0-9数字、小数点、正负数 可以进行加减乘除运算及简单的数学函数运算？
下面是使用 C 语言设计简易科学计算器的示例代码：
#include stdio.h
#include stdlib.h
#include math.h
int main()
{
char op;
double num1, num2;
printf("请输入数学表达式（如：1 + 2）：");
scanf("%lf %c %lf", num1, op, num2);
switch (op)
{
case '+':
printf("结果为：%.2lf\n", num1 + num2);
break;
case '-':
printf("结果为：%.2lf\n", num1 - num2);
break;
case '*':
printf("结果为：%.2lf\n", num1 * num2);
break;
case '/':
if (num2 == 0)
{
printf("除数不能为 0！\n");
}
else
{
printf("结果为：%.2lf\n", num1 / num2);
}
break;
case '^':
printf("结果为：%.2lf\n", pow(num1, num2));
break;
case 's':
printf("结果为：%.2lf\n", sin(num1));
break;
case 'c':
printf("结果为：%.2lf\n", cos(num1));
break;
case 't':
printf("结果为：%.2lf\n", tan(num1));
break;
case 'l':
printf("结果为：%.2lf\n", log(num1));
break;
case 'e':
printf("结果为：%.2lf\n", exp(num1));
break;
default:
printf("无效的运算符！\n");
break;
}
return 0;
}