c语言五子棋游戏编程代码自动(c语言实现简单的五子棋代码)
求一个用C语言编写五子棋游戏的全部代码.
这个程序还需要两个文件，告诉我你邮箱，我发给你
源程序前半部分
/*加载头文件*/
#includestdio.h
#includestdlib.h
#includegraphics.h
#includebios.h
#includeconio.h
/*编译预处理，定义按键码*/
#define LEFT 0x4b00
#define RIGHT 0x4d00
#define DOWN 0x5000
#define UP 0x4800
/*若想在游戏中途退出, 可按 Esc 键*/
#define ESC 0x011b
/*SPACE键表示落子*/
#define SPACE 0x3920
/*设置偏移量*/
#define OFFSET 20
#define OFFSET_x 4
#define OFFSET_y 3
/*定义数组大小*/
#define N 19
/*定义全局变量*/
int status[N][N]; /*定义的数组，保存状态*/
int step_x,step_y;/*行走的坐标*/
int key ; /*获取按下的键盘的键*/
int flag; /*玩家标志*/
/*自定义函数原型*/
void DrawBoard();
void DrawCircle(int x,int y,int color);
void Alternation();
void JudgePlayer(int x,int y);
void Done();
int ResultCheck(int x,int y);
void WelcomeInfo();
void ShowMessage();
/*定义函数*/
/*显示欢迎信息函数*/
void WelcomeInfo()
{
char ch ;
/*移动光标到指定位置*/
gotoxy(12,4);
/*显示欢迎信息*/
printf("Welcome you to gobang word!");
gotoxy(12,6);
printf("1.You can use the up,down,left and right key to move the chessman,");
gotoxy(12,8);
printf(" and you can press Space key to enter after you move it !");
gotoxy(12,10);
printf("2.You can use Esc key to exit the game too !");
gotoxy(12,12);
c语言基础，求五子棋详细代码
/*一个月就想做五子棋,有点难啊,希望你能看懂,这是代码*/
#include?stdlib.h
#include?stdio.h
#include?conio.h
#include?string.h
#define?MAXIMUS?15?//定义棋盘大小
int?p[MAXIMUS][MAXIMUS];//存储对局信息
char?buff[MAXIMUS*2+1][MAXIMUS*4+3];//输出缓冲器
int?Cx,Cy;//当前光标位置
int?Now;//当前走子的玩家，1代表黑，2代表白
int?wl,wp;//当前写入缓冲器的列数和行数位置
char*?showText;//在棋盘中央显示的文字信息
int?count;//回合数
char*?Copy(char*?strDest,const?char*?strSrc)//修改过的字符串复制函数，会忽略末端的\0
{
????char*?strDestCopy?=?strDest;
????while?(*strSrc!='\0')
????{
????????*strDest++=*strSrc++;
????}
????return?strDestCopy;
}
void?Initialize()//初始化一个对局函数
{
????int?i,j;//循环变量
????showText="";//重置显示信息
????count=0;//回合数归零
????for(i=0;iMAXIMUS;i++)//重置对局数据
????{
????????for(j=0;jMAXIMUS;j++)
????????{
????????????p[i][j]=0;
????????}
????}
????Cx=Cy=MAXIMUS/2;//重置光标到中央
????Now=1;//重置当前为黑方
}
char*?getStyle(int?i,int?j)//获得棋盘中指定坐标交点位置的字符，通过制表符拼成棋盘
{
????if(p[i][j]==1)//1为黑子
????????return?"●";
????else?if(p[i][j]==2)//2为白子
????????return?"○";
????else?if(i==0j==0)//以下为边缘棋盘样式
????????return?"┏";
????else?if(i==MAXIMUS-1j==0)
????????return?"┓";
????else?if(i==MAXIMUS-1j==MAXIMUS-1)
????????return?"┛";
????else?if(i==0j==MAXIMUS-1)
????????return?"┗";
????else?if(i==0)
????????return?"┠";
????else?if(i==MAXIMUS-1)
????????return?"┨";
????else?if(j==0)
????????return?"┯";
????else?if(j==MAXIMUS-1)
????????return?"┷";
????return?"┼";//中间的空位
}
char*?getCurse(int?i,int?j)//获得指定坐标交点位置左上格的样式，通过制表符来模拟光标的显示
{
????if(i==Cx)
????{
????????if(j==Cy)
????????????return?"┏";
????????else?if?(j==Cy+1)
????????????return?"┗";
????}
????else?if(i==Cx+1)
????{
????????if(j==Cy)
????????????return?"┓";
????????else?if?(j==Cy+1)
????????????return?"┛";
????}
????return?" ";//如果不在光标附近则为空
}
void?write(char*?c)//向缓冲器写入字符串
{
????Copy(buff[wl]+wp,c);
????wp+=strlen(c);
}
void?ln()//缓冲器写入位置提行
{
????wl+=1;
????wp=0;
}
void?Display()//将缓冲器内容输出到屏幕
{
????int?i,l=strlen(showText);//循环变量，中间文字信息的长度
????int?Offset=MAXIMUS*2+2-l/2;//算出中间文字信息居中显示所在的横坐标位置
????if(Offset%2==1)//如果位置为奇数，则移动到偶数，避免混乱
????{
????????Offset--;
????}
????Copy(buff[MAXIMUS]+Offset,showText);//讲中间文字信息复制到缓冲器
????if(l%2==1)//如果中间文字长度为半角奇数，则补上空格，避免混乱
????{
????????*(buff[MAXIMUS]+Offset+l)=0x20;
????}
????system("cls");//清理屏幕，准备写入
????for(i=0;iMAXIMUS*2+1;i++)//循环写入每一行
????{
????????printf("%s",buff[i]);
????????if(iMAXIMUS*2)//写入完每一行需要换行
????????????printf("\n");
????}
}
void?Print()//将整个棋盘算出并储存到缓冲器，然后调用Display函数显示出来
{
????int?i,j;//循环变量
????wl=0;
????wp=0;
????for(j=0;j=MAXIMUS;j++)//写入出交点左上角的字符，因为需要打印棋盘右下角，所以很以横纵各多一次循环
????{
????????for(i=0;i=MAXIMUS;i++)
????????{
????????????write(getCurse(i,j));//写入左上角字符
????????????if(j==0||j==MAXIMUS)//如果是棋上下盘边缘则没有连接的竖线，用空格填充位置
????????????{
????????????????if(i!=MAXIMUS)
????????????????????write(" ");
????????????}
????????????else//如果在棋盘中间则用竖线承接上下
????????????{
????????????????if(i==0||i==MAXIMUS-1)//左右边缘的竖线更粗
????????????????????write("┃");
????????????????else?if(i!=MAXIMUS)//中间的竖线
????????????????????write("│");
????????????}
????????}
????????if(j==MAXIMUS)//如果是最后一次循环，则只需要处理边侧字符，交点要少一排
????????{
????????????break;
????????}
????????ln();//提行开始打印交点内容
????????write(" ");//用空位补齐位置
????????for(i=0;iMAXIMUS;i++)//按横坐标循环正常的次数
????????{
????????????write(getStyle(i,j));//写入交点字符
????????????if(i!=MAXIMUS-1)//如果不在最右侧则补充一个横线承接左右
????????????{
????????????????if(j==0||j==MAXIMUS-1)
????????????????{
????????????????????write("━");//上下边缘的横线更粗
????????????????}
????????????????else
????????????????{
????????????????????write("—");//中间的横线
????????????????}
????????????}
????????}
????????ln();//写完一行后提行
????}
????Display();//将缓冲器内容输出到屏幕
}
int?Put()//在当前光标位置走子，如果非空，则返回0表示失败
{
????if(p[Cx][Cy]==0)
????{
????????p[Cx][Cy]=Now;//改变该位置数据
????????return?1;//返回1表示成功
????}
????else
????{
????????return?0;
????}
}
int?Check()//胜负检查，即判断当前走子位置有没有造成五连珠的情况
{
????int?w=1,x=1,y=1,z=1,i;//累计横竖正斜反邪四个方向的连续相同棋子数目
????for(i=1;i5;i++)//向下检查
????????if(Cy+iMAXIMUSp[Cx][Cy+i]==Now)
????????????w++;
????????else?
????????????break;
????for(i=1;i5;i++)//向上检查
????????if(Cy-i0p[Cx][Cy-i]==Now)
????????????w++;
????????else?
????????????break;
????if(w=5)//若果达到5个则判断当前走子玩家为赢家
????????return?Now;
????for(i=1;i5;i++)//向右检查
????????if(Cx+iMAXIMUSp[Cx+i][Cy]==Now)
????????????x++;
????????else?
????????????break;
????for(i=1;i5;i++)//向左检查
????????if(Cx-i0p[Cx-i][Cy]==Now)
????????????x++;
????????else?
????????????break;
????if(x=5)//若果达到5个则判断当前走子玩家为赢家
????????return?Now;
????for(i=1;i5;i++)//向右下检查
????????if(Cx+iMAXIMUSCy+iMAXIMUSp[Cx+i][Cy+i]==Now)
????????????y++;
????????else?
????????????break;
????for(i=1;i5;i++)//向左上检查
????????if(Cx-i0Cy-i0p[Cx-i][Cy-i]==Now)
????????????y++;
????????else?
????????????break;
????if(y=5)//若果达到5个则判断当前走子玩家为赢家
????????return?Now;
????for(i=1;i5;i++)//向右上检查
????????if(Cx+iMAXIMUSCy-i0p[Cx+i][Cy-i]==Now)
????????????z++;
????????else?
????????????break;
????for(i=1;i5;i++)//向左下检查
????????if(Cx-i0Cy+iMAXIMUSp[Cx-i][Cy+i]==Now)
????????????z++;
????????else?
????????????break;
????if(z=5)//若果达到5个则判断当前走子玩家为赢家
????????return?Now;
????return?0;//若没有检查到五连珠，则返回0表示还没有玩家达成胜利
}
int?RunGame()//进行整个对局，返回赢家信息(虽然有用上)
{
????int?input;//输入变量
????int?victor;//赢家信息
????Initialize();//初始化对局
????while(1)//开始无限回合的死循环，直到出现胜利跳出
????{
????????Print();//打印棋盘
????????input=getch();//等待键盘按下一个字符
????????if(input==27)//如果是ESC则退出程序
????????{
????????????exit(0);
????????}
????????else?if(input==0x20)//如果是空格则开始走子
????????{
????????????if(Put())//如果走子成功则判断胜负
????????????{
????????????????victor=Check();
????????????????Now=3-Now;//轮换当前走子玩家
????????????????count++;
????????????????if(victor==1)//如果黑方达到胜利，显示提示文字并等待一次按键，返回胜利信息
????????????????{
????????????????????showText="黑方获得了胜利！";
????????????????????Print();
????????????????????if(getch()==0xE0)
????????????????????{
????????????????????????getch();
????????????????????}
????????????????????return?Now;
????????????????}
????????????????else?if(victor==2)//如果白方达到胜利，显示提示文字并等待一次按键，返回胜利信息
????????????????{
????????????????????showText="白方获得了胜利！";
????????????????????Display();
????????????????????if(getch()==0xE0)
????????????????????{
????????????????????getch();
????????????????????}
????????????????????return?Now;
????????????????}
????????????????else?if(count==MAXIMUS*MAXIMUS)//如果回合数达到了棋盘总量，即棋盘充满，即为平局
????????????????{
????????????????????showText="平局！";
????????????????????Display();
????????????????????if(getch()==0xE0)
????????????????????{
????????????????????????getch();
????????????????????}
????????????????????return?0;
????????????????}
????????????}
????????}
????????else?if(input==0xE0)//如果按下的是方向键，会填充两次输入，第一次为0xE0表示按下的是控制键
????????{
????????????input=getch();//获得第二次输入信息
????????????switch(input)//判断方向键方向并移动光标位置
????????????{
????????????????case?0x4B:
????????????????Cx--;
????????????????break;
????????????????case?0x48:
????????????????Cy--;
????????????????break;
????????????????case?0x4D:
????????????????Cx++;
????????????????break;
????????????????case?0x50:
????????????????Cy++;
????????????????break;
????????????}
????????????if(Cx0)//如果光标位置越界则移动到对侧
????????????????Cx=MAXIMUS-1;
????????????if(Cy0)
????????????????Cy=MAXIMUS-1;
????????????if(CxMAXIMUS-1)
????????????????Cx=0;
????????????if(CyMAXIMUS-1)
????????????????Cy=0;
????????}
????}
}
int?main()//主函数
{
????system("title?简易五子棋?——Etsnarl制作");//设置标题
????system("mode?con?cols=63?lines=32");//设置窗口大小
????system("color?E0");//设置颜色
????while(1)//循环执行游戏
????{
????????RunGame();
????}
????return?0;
}
c语言的五子棋代码（博弈算法）
#include?stdio.h
#include?bios.h
#include?ctype.h
#include?conio.h
#include?dos.h
#define?CROSSRU?????0xbf???/*右上角点*/
#define?CROSSLU?????0xda???/*左上角点*/
#define?CROSSLD?????0xc0???/*左下角点*/
#define?CROSSRD?????0xd9???/*右下角点*/
#define?CROSSL???????0xc3???/*左边*/
#define?CROSSR???????0xb4???/*右边*/
#define?CROSSU???????0xc2???/*上边*/
#define?CROSSD???????0xc1???/*下边*/
#define?CROSS???????0xc5???/*十字交叉点*/
/*定义棋盘左上角点在屏幕上的位置*/
#define?MAPXOFT?????5
#define?MAPYOFT?????2
/*定义1号玩家的操作键键码*/
#define?PLAY1UP?????0x1157/*上移--'W'*/
#define?PLAY1DOWN???0x1f53/*下移--'S'*/
#define?PLAY1LEFT???0x1e41/*左移--'A'*/
#define?PLAY1RIGHT???0x2044/*右移--'D'*/
#define?PLAY1DO?????0x3920/*落子--空格键*/
/*定义2号玩家的操作键键码*/
#define?PLAY2UP?????0x4800/*上移--方向键up*/
#define?PLAY2DOWN???0x5000/*下移--方向键down*/
#define?PLAY2LEFT???0x4b00/*左移--方向键left*/
#define?PLAY2RIGHT???0x4d00/*右移--方向键right*/
#define?PLAY2DO?????0x1c0d/*落子--回车键Enter*/
/*若想在游戏中途退出,?可按?Esc?键*/
#define?ESCAPE???????0x011b
/*定义棋盘上交叉点的状态,?即该点有无棋子?*/
/*若有棋子,?还应能指出是哪个玩家的棋子???*/
#define?CHESSNULL???0???/*没有棋子*/
#define?CHESS1???????'O'/*一号玩家的棋子*/
#define?CHESS2???????'X'/*二号玩家的棋子*/
/*定义按键类别*/
#define?KEYEX99v?????????0/*退出键*/
#define?KEYFALLCHESS???1/*落子键*/
#define?KEYMOVECURSOR???2/*光标移动键*/
#define?KEYINVALID?????3/*无效键*/
/*定义符号常量:?真,?假?---?真为1,?假为0?*/
#define?TRUE?????????1
#define?FALSE???????0
/**********************************************************/
/*?定义数据结构???????????????????????????????????????????*/
/*棋盘交叉点坐标的数据结构*/
struct?point
{
int?x,y;
};
或者下面这个：
#include?graphics.h
#include?stdlib.h
#include?stdio.h
#include?conio.h
#define?N?15
#define?B?7
#define?STOP?-10000
#define?OK?1
#define?NO?0
#define?UP?328
#define?DOWN?336
#define?LEFT?331
#define?RIGHT?333
int?a[N+1][N+1];
int?zx,zy;
int?write=1,biaoji=0;
struct?zn{
long?sum;
int?y;
int?x;
}w[N+1][N+1],max,max1;
void?cbar(int?i,int?x,int?y,int?r);
void?map(int?a[][]);
int?getkey();
int?key();
void?zuobiao(int?x,int?y,int?i);
int?tu(int?a[][],int?write);
int?wtu(int?a[][],int?write);
int?zhineng(int?a[][]);
int?zh5(int?y,int?x,int?a[][]);
long?zzh5(int?b[][],int?i);
main()
{
int?i,j;
int?gdriver=DETECT;
int?gmode;
initgraph(gdriver,gmode,"");
zx=(N+1)/2;
zy=(N+1)/2;
for(i=1;i=N;i++)
for(j=1;j=N;j++)
a[i][j]=0;
map(a);
i=1;
while(i)
{
int?k,n;
k=wtu(a,write);
if(k==STOP)?goto?end;
map(a);
n=zhineng(a);
if(n==STOP)?goto?end;
map(a);
}
end:
;
}
int?zhineng(int?a[N+1][N+1])
{
int?i,j;
int?k;
max.sum=-1;
for(i=0;i=N;i++)
for(j=0;j+N;j++)
{
w[i][j].sum=0;
w[i][j].x=i;
w[i][j].y=j;
}
for(i=1;i=N-4;i++)
for(j=1;j=N-4;j++)
{
k=zh5(i,j,a);
if(k==STOP)?return?(STOP);
}
for(i=1;i=N;i++)
for(j=1;j=N;j++)
{
if(max.sumw[i][j].sum)
{
max.sum=w[i][j].sum;
max.y=i;
max.x=j;
}
else?if(max.sum==w[i][j].sum)
{
if(((max.y-zy)*(max.y-zy)+(max.x-zx)*(max.x-zx))((i-zy)*(i-zy)+(j-zx)*(j-zx)))
max.sum=w[i][j].sum;
max.y=i;
max.x=j;
}
}
if(a[max.y][max.x]==0)
{
a[max.y][max.x]=-1;
zy=max.y;
zx=max.x;
}
}
int?zh5(int?y,int?x,int?a[N+1][N+1])
{
int?i,j;
int?b[6][6];
long?c[13];
long?d[6][6];
long?temp;
for(i=y;i=y+4;i++)
for(j=x;j=x+4;j++)
b[i+1-y][j+1-x]=a[i][j];
c[1]=b[1][1]+b[1][2]+b[1][3]+b[1][4]+b[1][5];
c[2]=b[2][1]+b[2][2]+b[2][3]+b[2][4]+b[2][5];
c[3]=b[3][1]+b[3][2]+b[3][3]+b[3][4]+b[3][5];
c[4]=b[4][1]+b[4][2]+b[4][3]+b[4][4]+b[4][5];
c[5]=b[5][1]+b[5][2]+b[5][3]+b[5][4]+b[5][5];
c[6]=b[1][1]+b[2][1]+b[3][1]+b[4][1]+b[5][1];
c[7]=b[1][2]+b[2][2]+b[3][2]+b[4][2]+b[5][2];
c[8]=b[1][3]+b[2][3]+b[3][3]+b[4][3]+b[5][3];
c[9]=b[1][4]+b[2][4]+b[3][4]+b[4][4]+b[5][4];
c[10]=b[1][5]+b[2][5]+b[3][5]+b[4][5]+b[5][5];
c[11]=b[1][1]+b[2][2]+b[3][3]+b[4][4]+b[5][5];
c[12]=b[1][5]+b[2][4]+b[3][3]+b[4][2]+b[5][1];
for(i=1;i=12;i++)
{
switch(c[i])
{
case?5:biaoji=1;return(STOP);
case?-5:biaoji=-1;return(STOP);
case?-4:c[i]=100000;break;
case?4:c[i]=100000;break;
case?-3:c[i]=150;break;
case?3:c[i]=150;break;
case?-2:c[i]=120;break;
case?2:c[i]=100;break;
case?-1:c[i]=1;break;
case?1:c[i]=1;break;
default:?c[i]=0;
}
}
for(i=1;i=12;i++)
{
if(c[i]==150)
c[i]+=zzh5(b,i);
}
for(i=1;i=5;i++)
for(j=1;j=5;j++)
d[i][j]=0;
for(i=1;i=5;i++)
for(j=1;j=5;j++)
{
if(i==j)?d[i][j]+=c[11];
if((i+j)==6)?d[i][j]+=c[12];
d[i][j]+=c[i]+c[j+5];
}
for(i=1;i=5;i++)
for(j=1;j=5;j++)
{
if(b[i][j]!=0)
d[i][j]=-2;
}
max1.sum=-1;
max1.y=0;
max1.x=0;
for(i=1;i=5;i++)
for(j=1;j=5;j++)
{
if(max1.sumd[i][j])
{
max1.sum=d[i][j];
max1.y=i;
max1.x=j;
w[i+y-1][j+x-1].sum+=max1.sum;
}
else?if(max1.sum==d[i][j])
{
if(((i+y-1-zy)*(i+y-1-zy)+(j+x-1-zx)*(j+x-1-zx))((max1.y+y-1-zy)*(max1.y+y-1-zy)+(max1.x+x-1-zx)*(max1.x+x-1-zx)))
{
max1.sum=d[i][j];
max1.y=i;
max1.x=j;
}
}
}
}
long?zzh5(int?b[6][6],int?n)
{
int?i,j,k,l,m;
switch(n)
{
case?1:i=b[1][1];j=b[1][2];k=b[1][3];l=b[1][4];m=b[1][5];break;
case?2:i=b[2][1];j=b[2][2];k=b[2][3];l=b[2][4];m=b[2][5];break;
case?3:i=b[3][1];j=b[3][2];k=b[3][3];l=b[3][4];m=b[3][5];break;
case?4:i=b[4][1];j=b[4][2];k=b[4][3];l=b[4][4];m=b[4][5];break;
case?5:i=b[5][1];j=b[5][2];k=b[5][3];l=b[5][4];m=b[5][5];break;
case?6:i=b[1][1];j=b[2][1];k=b[3][1];l=b[4][1];m=b[5][1];break;
case?7:i=b[1][2];j=b[2][2];k=b[3][2];l=b[4][2];m=b[5][2];break;
case?8:i=b[1][3];j=b[2][3];k=b[3][3];l=b[4][3];m=b[5][3];break;
case?9:i=b[1][4];j=b[2][4];k=b[3][4];l=b[4][4];m=b[5][4];break;
case?10:i=b[1][5];j=b[2][5];k=b[3][5];l=b[4][5];m=b[5][5];break;
case?11:i=b[1][1];j=b[2][2];k=b[3][3];l=b[4][4];m=b[5][5];break;
case?12:i=b[1][5];j=b[2][4];k=b[3][3];l=b[4][2];m=b[5][1];break;
}
if((i==0j==1k==1l==1m==0))
return?(900);
if((i==0j==-1k==-1l==-1m==0))
return(1000);
if((i==0j==0k==1l==1m==1)||(i==1j==1k==1l==0m==0))
return(20);
if((i==0j==0k==-1l==-1m==-1)||(i==-1j==-1k==-1l==0m==0))
return(20);
if((i==-1j==1k==1l==1m==1)||(i==1j==-1k==1l==1m==1)||(i==1j==1k==-1l==1m==1)||(i==1j==1k==1l==-1m==1)||(i==1j==1k==1l==1m==-1))
return(-60);
if((i==1j==-1k==-1l==-1m==-1)||(i==-1j==1k==-1l==-1m==-1)||(i==-1j==1k==-1l==-1m==-1)||(i==-1j==-1k==-1l==1m==-1)||(i==-1j==-1k==-1l==-1m==1))
return(-60);
}
int?wtu(int?a[N+1][N+1],int?write)
{
int?i=1;
map(a);
zuobiao(zx,zy,1);
while(i)
{
int?k;
k=tu(a,write);
if(k==OK)?i=0;
if(k==STOP)?return?(STOP);
}
}
int?getkey()
{
int?key,lo,hi;
key=bioskey(0);
lo=key0x00ff;
hi=(key0xff00)8;
return((lo==0)???hi+256:lo);
}
int?key()
{
int?k;
k=getkey();
switch(k)
{
case?27:?return?(STOP);
case?13:
case?'?':?return?(OK);
case?328:?return?(UP);
case?336:?return?(DOWN);
case?331:?return?(LEFT);
case?333:?return?(RIGHT);
default:?return?(NO);
}
}
void?zuobiao(int?x,int?y,int?i)
{
int?r;
if(i!=0)
{
setcolor(GREEN);
for(r=1;r=5;r++)
circle(75+25*x,25+25*y,r);
}
else
{
if(a[zy][zx]==1)
{
setcolor(8);
for(r=1;r=5;r++)
circle(75+25*x,25+25*y,r);
}
else?if(a[zy][zx]==-1)
{
setcolor(WHITE);
for(r=1;r=5;r++)
circle(75+25*x,25+25*y,r);
}
else
{
setcolor(B);
for(r=1;r=5;r++)
circle(75+25*x,25+25*y,r);
setcolor(RED);?line(75+25*zx-5,25+25*zy,75+25*x+5,25+25*zy);
line(75+25*zx,25+25*zy-5,75+25*zx,25+25*zy+5);
}
}
}
int?tu(int?a[N+1][N+1],int?write)
{
int?k;
re:
k=key();
if(k==OK)
{
if(a[zy][zx]==0)
{
a[zy][zx]=write;
}
else
goto?re;
}
if(k==STOP)?return(STOP);
if(k==NO)?goto?re;
if(k==UP)
{
int?i,j;
if(zy==1)?j=zy;
else?j=zy-1;
zuobiao(zx,zy,0);
zuobiao(zx,j,1);
zy=j;
goto?re;
}
if(k==DOWN)
{
int?i,j;
if(zy==N)?j=zy;
else?j=zy+1;
zuobiao(zx,zy,0);
zuobiao(zx,j,1);
zy=j;
goto?re;
}
if(k==LEFT)
{
int?i,j;
if(zx==1)?i=zx;
else?i=zx-1;
zuobiao(zx,zy,0);
zuobiao(i,zy,1);
zx=i;
goto?re;
}
if(k==RIGHT)
{
int?i,j;
if(zx==N)?i=zx;
else?i=zx+1;
zuobiao(zx,zy,0);
zuobiao(i,zy,1);
zx=i;
goto?re;
}
}
void?cbar(int?i,int?x,int?y,int?r)
{
if(i!=0)
{
if(i==1)
setcolor(8);
else?if(i==-1)
setcolor(WHITE);
for(i=1;i=r;i++)
{
circle(x,y,i);
}
}
}
void?map(int?a[N+1][N+1])
{
int?i,j;
cleardevice();
setbkcolor(B);
setcolor(RED);
for(i=0;iN;i++)
{
line(100,50+25*i,75+N*25,50+25*i);
line(100+25*i,50,100+25*i,25+N*25);
}
for(i=1;i=N;i++)
for(j=1;j=N;j++)
cbar(a[i][j],75+25*j,25+25*i,10);
}
c语言五子棋代码，
package day17.gobang;
import java.util.Arrays;
public class GoBangGame {
public static final char BLANK='*';
public static final char BLACK='@';
public static final char WHITE='O';
public static final int MAX = 16;
private static final int COUNT = 5;
//棋盘
private char[][] board;
public GoBangGame() {
}
//开始游戏
public void start() {
board = new char[MAX][MAX];
//把二维数组都填充‘*’
for(char[] ary: board){
Arrays.fill(ary, BLANK);
}
}
public char[][] getChessBoard(){
return board;
}
public void addBlack(int x, int y) throws ChessExistException{
//@
//char blank = '*';
//System.out.println( x +"," + y + ":" + board[y][x] + "," + BLANK);
if(board[y][x] == BLANK){// x, y 位置上必须是空的才可以添棋子
board[y][x] = BLACK;
return;
}
throw new ChessExistException("已经有棋子了！");
}
public void addWhite(int x, int y)
throws ChessExistException{
if(board[y][x] == BLANK){// x, y 位置上必须是空的才可以添棋子
board[y][x] = WHITE;
return;
}
throw new ChessExistException("已经有棋子了！");
}
//chess 棋子：'@'/'O'
public boolean winOnY(char chess, int x, int y){
//先找到y方向第一个不是 blank的棋子
int top = y;
while(true){
if(y==0 || board[y-1][x]!=chess){
//如果y已经是棋盘的边缘， 或者的前一个不是chess
//就不再继续查找了
break;
}
y--;
top = y;
}
//向回统计所有chess的个数，如果是COUNT个就赢了
int count = 0;
y = top;
while(true){
if(y==MAX || board[y][x]!=chess){
//如果找到头 或者 下一个子不是chess 就不再继续统计了
break;
}
count++;
y++;
}
return count==COUNT;
}
//chess 棋子：'@'/'O'
public boolean winOnX(char chess, int x, int y){
//先找到x方向第一个不是 blank的棋子
int top = x;
while(true){
if(x==0 || board[y][x-1]!=chess){
//如果x已经是棋盘的边缘， 或者的前一个不是chess
//就不再继续查找了
break;
}
x--;
top = x;
}
//向回统计所有chess的个数，如果是COUNT个就赢了
int count = 0;
x = top;
while(true){
if(x==MAX || board[y][x]!=chess){
//如果找到头 或者 下一个子不是chess 就不再继续统计了
break;
}
count++;
x++;
}
return count==COUNT;
}
//chess 棋子：'@'/'O'
public boolean winOnXY(char chess, int x, int y){
//先找MAX向第一个不是 blank的棋子
int top = y;
int left = x;
while(true){
if(x==0 || y==0 || board[y-1][x-1]!=chess){
//如果x已经是棋盘的边缘， 或者的前一个不是chess
//就不再继续查找了
break;
}
x--;
y--;
top = y;
left=x;
}
//向回统计所有chess的个数，如果是COUNT个就赢了
int count = 0;
x = left;
y = top;
while(true){
if(x==MAX || y==MAX || board[y][x]!=chess){
//如果找到头 或者 下一个子不是chess 就不再继续统计了
break;
}
count++;
x++;
y++;
}
return count==COUNT;
}
//chess 棋子：'@'/'O'
public boolean winOnYX(char chess, int x, int y){
//先找到x方向第一个不是 blank的棋子
int top = y;
int left = x;
while(true){
if(x==MAX-1 || y==0 || board[y-1][x+1]!=chess){
//如果x已经是棋盘的边缘， 或者的前一个不是chess
//就不再继续查找了
break;
}
x++;
y--;
top = y;
left=x;
}
//向回统计所有chess的个数，如果是COUNT个就赢了
int count = 0;
x = left;
y = top;
while(true){
if(x==0 || y==MAX || board[y][x]!=chess){
//如果找到头 或者 下一个子不是chess 就不再继续统计了
break;
}
count++;
x--;
y++;
}
return count==COUNT;
}
public boolean whiteIsWin(int x, int y) {
//在任何一个方向上赢了，都算赢
return winOnY(WHITE, x, y) ||
winOnX(WHITE, x, y) ||
winOnXY(WHITE, x, y) ||
winOnYX(WHITE, x, y);
}
public boolean blackIsWin(int x, int y) {
return winOnY(BLACK, x, y) ||
winOnX(BLACK, x, y) ||
winOnXY(BLACK, x, y) ||
winOnYX(BLACK, x, y);
}
}
怎样用C语言编一个简单的五子棋游戏？
#include graphics.h
#include stdio.h
#include MATH.H
IMAGE* IMG;
IMAGE* IMG2;
IMAGE* IMG3;
IMAGE* whole;
bool mark = false;
int x = 0, y = 0;
int flag[15][15];
void show()
{
outtextxy(550, 100, "白方：");
outtextxy(550, 150, " 箭头移动");
outtextxy(550, 200, " 回车键落子");
outtextxy(550, 250, "黑方：");
outtextxy(550, 300, " ADWS移动");
outtextxy(550, 350, " 空格键落子");
}
int success1(int dir1, int dir2)
{
int number = 0;
int temp_x = x, temp_y = y;
while (((temp_x / 35 + dir1) = 0 (temp_x / 35 + dir1) 15) ((temp_y / 35 + dir2) = 0 (temp_y / 35 + dir2) 15) (flag[(temp_x / 35 + dir1)][(temp_y / 35 + dir2)] == 1))
{
temp_x = temp_x + dir1 * 35;
temp_y = temp_y + dir2 * 35;
++number;
}
return number;
}
int success2(int dir1, int dir2)
{
int number = 0;
int temp_x = x, temp_y = y;
while (((temp_x / 35 + dir1) = 0 (temp_x / 35 + dir1) 15) ((temp_y / 35 + dir2) = 0 (temp_y / 35 + dir2) 15) (flag[(temp_x / 35 + dir1)][(temp_y / 35 + dir2)] == 2))
{
temp_x = temp_x + dir1 * 35;
temp_y = temp_y + dir2 * 35;
++number;
}
return number;
}
int success1()
{
int number = 0;
number = success1(0, -1) + success1(0, 1);//上下
if (number 4)
{
number = success1(-1, 0) + success1(1, 0);//左右
if (number 4)
{
number = success1(-1, -1) + success1(1, 1);//左上右下
if (number 4)
{
number = success1(-1, 1) + success1(1, -1);//左下右上
}
}
}
return number;
}
int success2()
{
int number = 0;
number = success2(0, -1) + success2(0, 1);//上下
if (number 4)
{
number = success2(-1, 0) + success2(1, 0);//左右
if (number 4)
{
number = success2(-1, -1) + success2(1, 1);//左上右下
if (number 4)
{
number = success2(-1, 1) + success2(1, -1);//左下右上
}
}
}
return number;
}
void control()
{
char key = 0;
while (key != 27)
{
Sleep(10);
if (kbhit())
{
key = getch();
switch (key)
{
case VK_LEFT:
if (mark)
break;
if (x 0)
x = x - 35;
break;
case 'a':
case 'A':
if (!mark)
break;
if (x 0)
x = x - 35;
break;
case VK_RIGHT:
if (mark)
break;
if (x 490)
x = x + 35;
break;
case 'd':
case 'D':
if (!mark)
break;
if (x 490)
x = x + 35;
break;
case VK_UP:
if (mark)
break;
if (y 0)
y = y - 35;
break;
case 'w':
case 'W':
if (!mark)
break;
if (y 0)
y = y - 35;
break;
case VK_DOWN:
if (mark)
break;
if (y 490)
y = y + 35;
break;
case 's':
case 'S':
if (!mark)
break;
if (y 490)
y = y + 35;
break;
case VK_RETURN:
if (mark)
break;
if (flag[x / 35][y / 35] == 0)
{
putimage(whole, x + 6, y + 6, 31, 32, IMG2, 0, 0);
flag[x / 35][y / 35] = 1;
if (success1() = 4)
{
outtextxy(600, 50, "黑方 胜!");
key = 27;
}
mark = true;
}
break;
case VK_SPACE:
if (!mark)
break;
if (flag[x / 35][y / 35] == 0)
{
putimage(whole, x + 6, y + 6, 31, 31, IMG3, 0, 0);
flag[x / 35][y / 35] = 2;
if (success2() = 4)
{
outtextxy(600, 50, "白方 胜!");
key = 27;
}
mark = false;
}
break;
default:
break;
}
putimage(0, 0, whole);
putimage_transparent(NULL, IMG, x + 20, y + 20, 0x0, 0, 0, 20, 20);
}
}
}
void main()
{
setinitmode(0);
initgraph(800, 538);
SetWindowText(GetHWnd(), "五子棋20110327");
setcolor(0xffffff);
setfont(36, 0, "楷体_GB2312");
IMAGE* IMG1 = new IMAGE;
getimage(IMG1, "JPG", MAKEINTRESOURCE(102));//棋盘
putimage(0, 0, IMG1);
IMG2 = new IMAGE;
getimage(IMG2, "JPG", MAKEINTRESOURCE(103));//黑棋
IMG3 = new IMAGE;
getimage(IMG3, "JPG", MAKEINTRESOURCE(104));//白棋
IMG = new IMAGE;
getimage(IMG, "GIF", MAKEINTRESOURCE(101));//手形
whole = new IMAGE;
getimage(whole, 0, 0, 537, 537);
putimage_transparent(NULL, IMG, x + 20, y + 20, 0x0, 0, 0, 20, 20);
show();
control();
delete IMG1;
delete IMG2;
delete IMG3;
delete whole;
getch();
getch();
closegraph();
}