python怎么保存数据的均值(python保存中间数据)
python 问题 如何用python 求n个数的平均值 然后保留小数
# coding = GBK
a =[1,2,3,4,5]
sum=0
b = len(a)
print("这个数组的长度为：",b)
for i? in a:
sum =sum +i
print("这个数组之和为：",sum)
print("这个数组平均数为",sum/b)
或
import sys
sum = 0
cnt = 0
f = open('1.txt', 'r')
files = f.readline()
while (files ):
sum = sum + float(files .split(",")[0])
cnt = cnt + 1
files = f.readline()
print(sum / cnt)
f.close()
或者。
#!/usr/bin/env pythonimport timeimport numpy as np
dd = np.random.randint(0, 20, size=(2*1000*1000))t_start = time.clock()avg_sum1 =
0.0BlockOffset = 0 ? ? while BlockOffset len(dd):
if dd[BlockOffset + 1] = 10:
avg_sum1 += dd[BlockOffset + 1] * 0.1
else:
avg_sum1 += dd[BlockOffset + 0] * 0.01
BlockOffset += 2print('Avg: ' + str(avg_sum1 / len(dd) / 2)) ? ?print('Exe time: ' +
str(time.clock() - t_start))
扩展资料：
python 实现求和、计数、最大最小值、平均值、中位数、标准偏差、百分比。
import?sys
class?Stats:
def?__init__(self, sequence):
# sequence of numbers we will process
# convert all items to floats for numerical processing
self.sequence?=?[float(item)?for?item?in?sequence]
def?sum(self):
if?len(self.sequence) ?1:
return?None
else:
return?sum(self.sequence)
def?count(self):
return?len(self.sequence)
def?min(self):
if?len(self.sequence) ?1:
return?None
else:
return?min(self.sequence)
def?max(self):
if?len(self.sequence) ?1:
return?None
else:
return?max(self.sequence)
def?avg(self):
if?len(self.sequence) ?1:
return?None
else:
return?sum(self.sequence)?/?len(self.sequence)?
def?median(self):
if?len(self.sequence) ?1:
return?None
else:
self.sequence.sort()
return?self.sequence[len(self.sequence)?//?2]
def?stdev(self):
if?len(self.sequence) ?1:
return?None
else:
avg?=?self.avg()
sdsq?=?sum([(i?-?avg)?**?2?for?i?in?self.sequence])
stdev?=?(sdsq?/?(len(self.sequence)?-?1))?**?.5
return?stdev
def?percentile(self, percentile):
if?len(self.sequence) ?1:
value?=?None
elif?(percentile =?100):
sys.stderr.write('ERROR: percentile must be 100.? you supplied: %s\n'%?percentile)
value?=?None
else:
element_idx?=?int(len(self.sequence)?*?(percentile?/?100.0))
self.sequence.sort()
value?=?self.sequence[element_idx]
return?value
用python做一个程序，能够存储数据并输出平均值
这么简单实现行吗
sum?=?0.0
count?=?0
with?open('numbers.txt',?'a')?as?f:
????while?True:
????????value?=?input('Input?number:')
????????if?value?==?'':
????????????break
????????sum?=?sum?+?float(value)
????????count?+=?1
????????f.write(value?+?'\n')
????f.write('avg=?'?+?str(sum?/?count)?+?'\n')
????print('avg=?'?+?str(sum?/?count)?+?'\n')
python怎么求平均值及所有大于平均值的数？
题主你好,
代码及测试截图如下:
希望可以帮到题主, 欢迎追问
python怎么将学生的成绩保存成字典 并返回三门课的平均值
global students
students={
"Zhangsan":(89,88,80),
"Bill":(90,90,86),
"Tom":(80,98,85),
"Jack":(79,90,89)}
def average(*shu):
(Tab缩进)AVE=sum(shu)/len(shu)
(Tab缩进)return AVE
def average_courses(name):
(Tab缩进)for k,v in students.items():
(Tab缩进)(Tab缩进)if k==name:
(Tab缩进)(Tab缩进)(Tab缩进)return [name, v, round(average(*v), 1)]
if __name__ == "__main__":
(Tab缩进)#print(average_courses("Tom"))
(Tab缩进)#print(average_courses("Tom")[2])
(Tab缩进)for k in students.keys():
(Tab缩进)(Tab缩进)print([k,average_courses(k)[2]])
'''python运行效果
['Zhangsan', 85.7]
['Bill', 88.7]
['Tom'