python画圆代码(python画圆代码重叠)
python 绘制一个圆,当单击窗口的任意位置时圆移动到单击的位置,如何编写代码？
#-*-?coding:?UTF-8?-*-
import?pygame,?sys
from?pygame.locals?import?*
white?=?255,?255,?255
blue?=?0,?0,?200
pygame.init()
screen?=?pygame.display.set_mode((600,?800))
myfont?=?pygame.font.Font(None,?20)
textImage?=?myfont.render("hello?game",?True,?white)
position?=?200,?200
print(position)
while?True:
for?event?in?pygame.event.get():
if?event.type?in?(QUIT,?KEYDOWN):
sys.exit()
elif?event.type?==?MOUSEBUTTONDOWN:
position?=?event.pos
screen.fill(blue)
screen.blit(textImage,?(100,?100))
#position?=?200,?200
radius?=?100
width?=?10
pygame.draw.circle(screen,?white,?position,?radius,?width)
pygame.display.update()
用pygame创建界面并监控鼠标按下事件，获得按下位置，画圆
代码注意缩进如下图：
用python画一个圆
###################################
# coding=utf-8
# !/usr/bin/env python
# __author__ = 'pipi'
# ctime 2014.10.11
# 绘制椭圆和圆形
###################################
from matplotlib.patches import Ellipse, Circle
import matplotlib.pyplot as plt
fig = plt.figure()
ax = fig.add_subplot(111)
ell1 = Ellipse(xy = (0.0, 0.0), width = 4, height = 8, angle = 30.0, facecolor= 'yellow', alpha=0.3)
cir1 = Circle(xy = (0.0, 0.0), radius=2, alpha=0.5)
ax.add_patch(ell1)
ax.add_patch(cir1)
x, y = 0, 0
ax.plot(x, y, 'ro')
plt.axis('scaled')
# ax.set_xlim(-4, 4)
# ax.set_ylim(-4, 4)
plt.axis('equal') #changes limits of x or y axis so that equal increments of x and y have the same length
plt.show()
你可以试试，谢谢。
python怎么在不同点上画相交的圆
1、首先进入软件主界面，使用python编程语言。
2，其次在用matplotlib画图的模板。
3、最后利用参数方程会来画圆即可画出不同点上画相交的圆。
Python语句中light.circle(20)中20指的什么意思？
圆的直径
python画圆代码from matplotlib.patches import Ellipse, Circle
import matplotlib.pyplot as plt
def plot_cicle():
fig = plt.figure()
ax = fig.add_subplot(111)
cir1 = Circle(xy = (0.0, 0.0), radius=2, alpha=0.5)
ax.add_patch(cir1)
x, y = 0, 0
ax.plot(x, y, 'ro')
plt.axis('scaled')
plt.axis('equal') #changes limits of x or y axis so that equal increments of x and y have the same length
plt.show()
plot_cicle()