大一python编程题库和答案(大一python代码)

http://www.itjxue.com  2023-03-25 01:18  来源:未知  点击次数: 

Python编程题求助

该答案为组合数学中著名的卡特兰数,其通式为C(2n,n)-C(2n,n-1)

这里采用递推关系求解,即动态规划的方法

设n对父子有d[n]种出场策略,注意初值d[0]=1

因为每个孩子前面必有一个父亲与之对应

对于i对父子,遍历第j个孩子,该孩子前面有j-1个孩子,对应d[j-1]种出场策略

后面有i-j个孩子,对应d[i-j]种出场策略,则d[i]+=d[j-1]*d[i-j],最终d[n]即为所求

python代码如下:

n = int(input())

d = [0] * (n+1)

d[0] = 1

for i in range(n+1):

? for j in range(i+1):

? ? ? d[i] += d[j-1] * d[i-j]

print(d[n])

运行结果如下:

望采纳~

关于python程序设计题的题库?

1、average_sum函数的功能为求一批数中大于平均值

sum=0

k=0

for i in range(n):

sum=sum+a[i]

average=sum/n

for i in range:

if(a[i]average):

k=k+a[i]

return k

2、编写函数fun求一个不多于五位数的正整数的位数

if(m9999):

place=5

elif(m999):

place=4

elif(m99):

place=3

elif(m9):

place=2

else:

place=1

return place

3、请编fun函数,求4*4整形数组的主对角线元素的和

sum=0.0

for i in range(4):

sum+=a[i][i]

return sum

4、已知:一元钱一瓶汽水,喝完后两个空瓶换一瓶汽水。问:请输入钱数(大于1的正整数),则根据钱数最多可以喝到几瓶汽水。

s=0

k=0

while m0:

m=m-1

s=s+1

k=k+1

while k=2:

k=k-2

s=s+1

k=k+1

return s

5、编写函数fun(x,y),函数的功能是若x、y为奇数,求x到y之间的奇数和;若x、y为偶数,则求x到y之间的偶数和。要求必须使用for结构。

主函数的功能是分别计算如下的值:

(1+3+5+……+777)+(2+4+6+……+888)=???

(1+3+5+……+1111)+(2+4+6+……+2222)=???

(1+3+5+……+1999)+(2+4+6+……+1998)=???

s=0

for i in range(x,y+1,2):

s=s+i

return s

6、编写函数main 求3!+6!+9!+12!+15!+18!+21!

s=0

for i in range(3,22,3):

r=1

for j in range(1,i+1):

r*=j

s+=r

print(s)

python 编程 求答案!2、3两题

#!/usr/bin/env?python

#coding=utf-8

import?re

from?datetime?import?datetime?as?dt,?timedelta

import?platform

if?platform.python_version()[:1]?==?'2':?#判断python版本是2还是3

????import?sys

????reload(sys)

????sys.setdefaultencoding('utf8')

class?Idcard(object):

????'''?

?????m?=?Idcard('225122198611134730')

?????print(m.sex)

????男

?????m.birth

????'1986-11-13'

?????m.age

????30

????'''

????def?__init__(self,idcard):

????????self.idcard?=?idcard????????

????????if?len(idcard)?==?15:

????????????sex,?birth?=?idcard[-1:],?'19'?+?idcard[6:12]

????????elif?len(idcard)?==?18:

????????????sex,?birth?=?idcard[-2:-1],?idcard[6:14]???

????????else:

????????????raise?Exception('len(idcard)?is?{}?(15/18)'.format(len(idcard)))

????????self._sex?=?int(sex)?%?2

????????self._birth?=?birth

????

????@property

????def?sex(self):

????????return?u'男'?if?self._sex?%?2?else?u'女'

????@property

????def?age(self):??

????????now,?bir?=?dt.now(),?dt.strptime(self._birth,?'%Y%m%d')

????????beforebirth?=?(now?-?dt(now.year,?bir.month,?bir.day)).days??0

????????return?dt.now().year?-?int(self._birth[:4])?-?beforebirth

????@property

????def?birth(self):

????????return?dt.strptime(self._birth,?'%Y%m%d').strftime('%Y-%m-%d')

def?alignment(str1,?space,?align?=?'left'):

????length?=?len(str1.encode('gb2312'))

????space?=?space?-?length?if?space?=length?else?0

????if?align?==?'left':

????????str1?=?str1?+?'?'?*?space

????elif?align?==?'right':

????????str1?=?'?'*?space?+str1

????elif?align?==?'center':

????????str1?=?'?'?*?(space?//2)?+str1?+?'?'*?(space?-?space?//?2)

????return?str1

????

def?main():

????fname?=?'customer.txt'

????'''

????with?open(fname,?'w')?as?f:

????????f.write("""

????????郑文杰?225122198611134730

????????文萍?225122198912094740

????????郑妈妈??225122590303476

????????郑爸爸?225122560506471

????????""")

????'''????

????newf?=?'ourcustomers.txt'

????with?open(fname)?as?f:

????????s?=?f.readlines()

????L,?newL?=?[re.split(r'\s+',?i.strip())?for?i?in?s],?[]

????for?i?in?L:

????????if?len(i)?==?2:

????????????g?=?Idcard(i[1])

????????????newL.append('{}{}{}'.format(

????????????????alignment(i[0],?10),?alignment(g.sex,?8),?g.age))

????with?open(newf,?'w')?as?f:

????????f.write('\n'.join(newL))

????print('\n'.join(newL[:100]))

????print('Customer?data?has?been?write?into?{}'.format(newf))

if?__name__?==?'__main__':

????import?doctest

????doctest.testmod()

????main()

(责任编辑:IT教学网)

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